HabitableZone

Off Topic » in reply to E = cm^2 divided by m and multiplied by c.

I see what you mean, so lets try another method.

E = (u/k) c. Where c= a constant that is represented by the speed of light in meters per second within a vacuum of space. And m= mass measured in kilograms. And “u” represents the potential force that is intrinsic to the quantity of mass; that potential force is calculated by multiplying the mass quantity by itself and then by multiplying the result by c, in other words m^2 times “c”. E= energy in Joules.
We know that C is approximately 300,000,000 meters per second.
If we take a 5 kilogram mass as an example and use it in the formula we will get the following result.
If m = 5, then u will = 25 * c, and that = 7,500,000,000
Now we have all the figures that we need to make the calculation: U= 7,500,000,000 and m=5 so we first take the 7,500,000,000 and divide it by 5 to get 1,500,000,000, which represents the kinetic energy that is intrinsic to that quantity of mass, then we multiply that figure by the “c”; in our example we are using 300,000,000 m/s as a close enough number for c, and that means that 1,500,000,000 * 300,000,000 = 4.5*10^17 Joules.
This way of looking at the structure of mass indicates that the “mass” as we know it, is composed of three fundamental ingredients, one is space, which contains potential force and is the volume that movement can happen in, the second is the kinetic force which manifests itself as the density that is able to move in the space, and the third is the kinetic energy that causes the motion of the density within the space.
In other words, the symbol “u/k” in the formula indicates the structure of mass with its intrinsic space, density and motion. When such a combination is accelerated to the maximum speed then it will contain the maximum energy.

The book that this information was deciphered from, was translated from another language in 1861. The copy that I have was printed in 1927.

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