Space/Science — HabitableZone

Space/Science » in reply to Re Orbit the Moon

Tradeoffs

Everything on spacecraft involves tradeoffs. Imaging the lunar surface at a 1 cm resolution would require handling a tremendous amount of data. According to this source, the moon has a surface area of 37.8 million square km. A single square kilometer has 10,000,000,000 (10^10) square centimeters, so the approximate surface area of the moon is 378,000,000,000,000,000 (3.78 * 10^17) square centimeters. You'd have to allow for a reasonable amount of overlap between the images, so you'd probably be looking at 500 quadrillion (5 * 10^17) square centimeters.

If you image in standard grayscale (256 shades per pixel), then the raw image size would be at least 500 terrabytes. Color images would multiply that number by as much as a factor of 3-4, and multispectral imaging would be even bigger.

Imaging a single square kilometer at 1 cm resolution would require at least 10 gigabytes of on board memory to hold the image plus more memory if you want to use compression. GIF compression works really well on grayscale with no losses, typically achieving compression factors of 2-3. JPEG compression can achieve higher compression factors but requires more processing and involves losing some data.

In the end, you might be able to reduce that 10 gigabyte image to 1 gigabyte while maintaining good image quality. Now, you have to transmit that image back to Earth. Transmitting from the moon is much easier than from Mars, but you're still controlled by factors like antenna gain, transmitter power, receiver antenna and system sensitivity, and system availability. DSN resources are limited so you might want to set up 3 dedicated antennas 120 degrees apart on Earth to receive the transmissions.

Suppose you can achieve a reliable 1 megabit data transfer rate for the downlink. Transmitting a single 1 gigabyte image would require 133.33 minutes. Oops, that's over 2 hours. From the Apollo days, a single lunar orbit takes roughly 2 hours with about 40 minutes of that time being out of communications. OK, lets push the downlink to 10 megabits per second, so the time to transmit one image drops to about 13.33 minutes. If the orbit is 120 minutes with 80 minutes available for communications, you could transmit 6 images per rev. At that rate, imaging all 37.8 million square kilometers of the lunar surface (and pushing the total up to 50 million to allow for overlaps) would take 6.3 million orbits. At 2 hours each orbit and xxxx hours per year, that would take about 1438 years.

We could try to boost the downlink to much higher speeds, say 1 gigabit per second. That would require a combination of higher transmitter power, much higher antenna gain on both ends, which requires much higher pointing accuracy. Higher frequencies like EHF would also help but they're subject to atmospheric attenuation. You'd need to boost the amount of data storage on the spacecraft to a terrabyte or more and it should be radiation hardened to prevent data corruption due to cosmic rays. All of these things would drive up the costs substancially and it'd still take 14 years to image all of the moon.

Perhaps 1 cm resolution isn't the way to go. Perhaps something more reasonable, like 50 cm resolution would be sufficient. After all, virtually all of the existing lunar images are taken at resolutions of about 50 meters or worse, so a factor of 100 improvement in resolution would be a big step in the right direction.

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