Space/Science — HabitableZone

Space/Science » in reply to Attn: R.L. -- Ask and thou shall receive.

When did I ask for crap? (read carefully, dimwit)

First, allow me to demonstrate that you are incompetent at simple grade school multiplication...

You state the following:

If 2 kilograms (70.5479239614 ounces ) of mass is converted totally to energy the quantity of energy will be as follows:

M2=4 K0=2
U=4*299792458=1199169832
U/k=1199169832/2=599584916
E=599584916*299792458=1.7975103575e17 joules
.........

According to R.L.’s estimation it takes about 6*10^24 J to heat the Earth’s atmosphere and ocean by one degree, then according to R.L. all we need to do is convert 2 kilograms of mass into energy every sixty thousands of a second for a duration of one second to heat the atmosphere by one degree and have some energy left over.....


Ok nimrod... ignoring your stupid rewrite of e=mc^2, since when does (1.8*10^17)* 60,000 equal 6*10^24?! again you are off by orders of magnitude! You dont understand a damn thing about basic math or fission- as others have already pointed out...

I am going to ignore most of the other drivel in your post and answer the one question others havent answered and shown you to be ignorant....

You asked how much uranium must be consumed in fission to convert 2kg of mass into energy...

Ok here we go:
Energy released from 1 atom of U235 going fission: 2*10^8 eV= 3.2*10^-11 J
mass to energy in one U235 fission: 3.5*10^-28 kg
mass of U235 atom= ~ 3.9*10^-25 kg

number of fusion events to turn 2 kg of mass into energy: 5.7*10^27 events

mass of U235 atoms that must fission to turn 2 kg into energy (and remember the amount of U235 needed will be MUCH greater than the number of atoms that actually split) is :

(5.7*10^27)*( 3.9*10^-25)=2.2*10^3 kg

Now to heat the earths ocean and atmosphere by 1 degree, I calculated you need 6*10^24 J (actually the true amount is ORDERS OF MAGNITUDE MORE since I did not include the thermalization of the earth itself, or the energy radiated to space)...

the mass of U235 that must fission is (2.2*10^3 kg)*(6*10^24 J)/(1.8*10^17 J)=2.2*10^3 kg *(3.3*10^7)= 7.26*10^10 kg to fission!!!!!!

that is SEVENTY _BILLION_ KILOGRAMS!!!!!!!!!!

NOW WILL YOU DROP THIS NONSENSE?!

you are wrong- demonstrably so- you just advertise your ignorance and stupidity when you post this crap....
You are wrong by MANY MANY ORDERS OF MAGNITUDE!!!
As Nick said "GET AN EDUCATION!"

YOU are too lazy and stupid to run the numbers yourself, and when we do them for you, you put your fingers in your ears and close your eyes and keep posting garbage...

In _all_ my back of the envelope calculations I made only assumptions that helped your case, and effects I ignored, if included, would only help
-my- case and still we get 70 billion kg!!! Go play in another sandbox, kid- the adults here are tired of changing your mental diapers...

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