Entropy change of Solid’s thermal circulation
My English is not good.My friend Dr Ke Jiang Ling help me traslate in English.His English is good.
I am working at Guangdong China.
There is an independent relationship between solid’s elastic potential energy and heat energy: When the outside world gives the solid a pressure force, it shrinks, then function transforms into elastic potential energy. Suppose the degree of transformation is very little ( close to zero), so when the outside force withdraws, the elastic energy is released and does function, which is equal to the former function consumed. And if the energy exchange between them is considerable, then the relationship between pressure force and contract is not linear.
Maybe they have some other relationship. Let us do an experiment. Having been heated from 20 CO to 25CO, the solid volume expands, and the heat energy absorbed from the environment is supposed as Q1. Then shrink the solid to the situation its volume is equal to the beginning, and suppose the function done by the outside is W. So the increase of energy in the system is Q1+W, but the temperature is constant. This system must absorb the energy Q2. Because the two final situation is same. So Q2=Q1+W

But the specific heat is different, c1<C2
Let us do a circulation, firstly we heat the solid isovolumetricly to Q2, then do W’s function when expanding, and cool the solid by releasing energy Q1 to make the temperature same as the beginning.

Entropy change
dS=dQ2/T+dQ1/T=c2*dT/T-c1*dT/T
Because of c1<C2, when the circulation completes, DS(entropy change)>0
But in Clausius law, he think DS=0, so when he see the above result, what does he think about?