Space/Science — HabitableZone

Space/Science » in reply to Its quite simple to calculate- I am sure several here can do the math, but dont post the answer- lets wait for super genius, 'better than Einstein' Johannes to share his answer first...

re: My curiosity was directed at “ Adam, posted on 3/24/2007 5:06:04 AM,“ he

is the one that mentioned the 250 watt power figure for a kilogram of nuclear material. See: “ http://www.habitablezone.com/nexus/index.asp?svcpt=offtopic “

even nuclear reactors struggle putting out 250 W of electrical power for every kilogram of mass.


And my comment/question was directed to the “efficiency” of the energy conversion.

As for the math problem you present, could you be more specific as to how your math solution explains the “efficiency” of a nuclear power plant.
Although I did not look for in-depth research into this subject at the moment, I will try to answer your question.

One watt of power is 1 Joule of energy, at least according to my understanding of the math formulas.
There are many sites on the internet explaining that relationship, one site is:
http://hyperphysics.phy-astr.gsu.edu/hbase/work.html

I assume that by “one ton” you mean a metric ton.
One metric ton equals thousand kilograms.
If a metric ton of TNT releases ~4.2 GJ of energy, then (I assume that) one thousandth of a ton or 1Kg of that amount releases ~.0042GJ of energy and that is the same amount of power in watts.

Even if I’m way off with my calculation, which I did by moving the decimal point three digits to the left, the formula: E=(U/K)C is still correct.

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