Whether you boil or evaporate water it requires
2.26 * 10^6 Joules.

"Approximately 505,000 km³ of water fall as precipitation each year, 398,000 km³ of it over the oceans"
http://en.wikipedia.org/wiki/Water_cycle

Energy is used to evaporate and the energy is released when the water returns to liquid state

505,000 cubic km is 5.05 x 10^17 kg of water.

The amount of energy required to evaporate
5.05 x 10^17 kg of water is 5.05 x 10^17 kg
times 2.26 * 10^6 Joules:
1.1413 * 10^24 joules
Which equal to a bit less then 1/3rd of the yearly solar energy that reaches earth surface.

The amount time that the sun's energy is stored as evaporated water is in the order of days before the energy is released by the condensation back into liquid and is measured as rain.
Any water which is evaporated which doesn't form into clouds and subsequently rains is not counted.

So, any water vapor which for instance directly condenses onto a cold object wouldn't be counted- whether the object is a rock or other water.

So, the 1.1413 * 10^24 joules is a measured amount energy which stored and then released.

On average on any given day, a 1/3rd of the Sun's energy is lost and that energy will be "found" a few days later perhaps hundreds of miles away.
It should be possible that 3 or more days of stored energy is released in one day [globally- not locally], or even a freakish couple hours- thereby providing one day of solar energy within a given time period.